Solve the following equation. b+(b+1)+(b+2)4=21 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

Solve the following equation.

`("b" + ("b" + 1) + ("b" + 2))/4 = 21`

Sum

`("b" + ("b" + 1) + ("b" + 2))/4 = 21`

Multiplying both sides by 4

⇒ 4 x `("b" + ("b" + 1) + ("b" + 2))/4 = 4 xx 21`

⇒ b + (b + 1) + (b + 2) = 84

⇒ 3b + 3 = 84

Subtracting 3 from both sides

⇒ 3b + 3 - 3 = 84 - 3

⇒ 3b = 81

Dividing both sides by 3

⇒ `(3"b")/3 = 81/3`

⇒ b = 27

Hence, b = 27 is the solution of the equation.

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Solution of Equations in One Variable

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Chapter 12: Equations in one variable - Practice Set 12.1 [Page 77]

Chapter 12 Equations in one variable
Practice Set 12.1 | Q 2.11 | Page 77

Chapter 3.3 Equations in One Variable
Practice Set 12.1 | Q 2. (11) | Page 52