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Maharashtra State BoardSSC (English Medium) 8th Standard

The equation given below is followed by the value of the variable. Decide whether this value is the solution to that equation. 2a + 4 = 0, a = 2, −2, 1 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

The equation given below is followed by the value of the variable. Decide whether this value is the solution to that equation.

 2a + 4 = 0, a = 2, −2, 1

Sum

Solution

2a + 4 = 0   ...(i)

Substituting a = 2 in L.H.S. of equation (i),

L.H.S. = 2 (2) + 4

= 4 + 4

= 8

R.H.S. = 0

∴ L.H.S. ≠ R.H.S.

∴ a = 2 is not the solution of the given equation.

Substituting a = – 2 in L.H.S. of equation (i),

L.H.S. = 2 (–2) + 4

= – 4 + 4

= 0

R.H.S. = 0

∴L.H.S. = R.H.S.

∴ a = – 2 is the solution of the given equation.

Substituting a = 1 in L.H.S. of equation (i),

L.H.S. = 2(1) + 4

= 2 + 4

= 6

R.H.S. = 0

∴ L.H.S. ≠ R.H.S.

∴ a = 1 is not the solution of the given equation.

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Solution of Equations in One Variable
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Chapter 12: Equations in one variable - Practice Set 12.1 [Page 77]

APPEARS IN

Balbharati Mathematics [English] 8 Standard Maharashtra State Board
Chapter 12 Equations in one variable
Practice Set 12.1 | Q 1.3 | Page 77
Balbharati Integrated 8 Standard Part 3 [English Medium] Maharashtra State Board
Chapter 3.3 Equations in One Variable
Practice Set 12.1 | Q 1. (3) | Page 52
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