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प्रश्न
Solve the following numerical problem.
What effort will be required to lift a load of 500 N by a single movable pulley? [Hint: Mechanical advantage of a single movable pulley is two].
उत्तर
Load = 500 N
Mechanical advantage (M A) = 2
of a single movable pulley
Effort =?
We know that,
MA = `"Load "/"Effort"`
⇒ Effort = `500/2` N = 250 N
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संबंधित प्रश्न
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In a single movable pulley system, a load of 125 kgf is lifted by an effort of 75 kgf. Find the percentage efficiency of system.
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