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प्रश्न
Solve the following numerical problem.
What effort will be required to lift a load of 500 N by a single movable pulley? [Hint: Mechanical advantage of a single movable pulley is two].
उत्तर
Load = 500 N
Mechanical advantage (M A) = 2
of a single movable pulley
Effort =?
We know that,
MA = `"Load "/"Effort"`
⇒ Effort = `500/2` N = 250 N
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संबंधित प्रश्न
A pulley system with VR = 4 is used to lift a load of 175 kgf through a vertical height of 15 m. The effort required is 50 kgf in the downward direction.
(g = 10 N kg-1)
Calculate
1) Distance moved by the effort
2) Work done by the effort
3) M.A. of the pulley system
4) Efficiency of the pulley system
From the diagram given below. answer the question that follows:
1) What kind of pulleys are A and B?
2) State the purpose of pulley B.
3) What effort has to be applied at C just raise the load L = 20 kgf?
(Neglect the weight of pulley A and friction)
Draw a neat labelled diagram showing a pulley being used to lift a load. How are load and effort related in an ideal situation?
Name a machine to change the direction of force ?
Explain how a gear system can be used to obtain gain in torque? Given one example.
The mechanical advantage of an ideal single movable pulley is ______.
Name the type of single pulley that can act as a force multiplier. Draw a labeled diagram of the pulley mentioned by you.
Give reason for the following:
The efficiency of a pulley is always less than 100%
State two reasons, why the efficiency of a pulley system is not 100 percent?
A block and tackle system of pulleys has a velocity ratio of 4.
- Draw a labelled diagram of the system indicating clearly the points of application and directions of load and effort.
- What is the value of the mechanical advantage of the given pulley system if it is an ideal pulley system?
