Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by formula method
3y2 – 20y – 23 = 0
उत्तर
a = 3, b = – 20, c = – 23
x = `(-"b" ± sqrt("b"^2 - 4"ac"))/(2"a")`
= `(20 ± sqrt(400 - 4(3) (- 23)))/(6)`
= `(20 ± sqrt(400 + 276))/(6)`
= `(20 ± sqrt(676))/(6)`
= `(20 ± 26)/(6)`
= `(2(10 ± 13))/(6)`
= `((10 ± 13))/(3)`
= `(10 + 13)/(3)` or `(10 - 13)/(3)`
= `(23)/(3)` or `(-3)/(3) = (23)/(3)` or – 1
The solution set is – 1 and `(23)/(5)`
APPEARS IN
संबंधित प्रश्न
Find the sum and product of the roots for the following quadratic equation
x2 + 3x – 28 = 0
Find the sum and product of the roots for the following quadratic equation
3y2 – y – 4 = 0
Solve the following quadratic equation by completing the square method
9x2 – 12x + 4 = 0
Solve the following quadratic equation by formula method
36y2 – 12ay + (a2 – b2) = 0
A bus covers a distance of 90 km at a uniform speed. Had the speed been `(15"km")/"hour"` more it would have taken 30 minutes less for the journey. Find the original speed of the bus
Determine the nature of the roots for the following quadratic equation
x2 – x – 1 = 0
The roots of the equation 2x2 – 7x + 5 = 0 are α and β. Without solving for the roots, find `1/alpha + 1/beta`
If one root of the equation 2y2 – ay + 64 = 0 is twice the other then find the values of a
If one root of the equation 3x2 + kx + 81 = 0 (having real roots) is the square of the other then find k
The number of points of intersection of the quadratic polynomial x2 + 4x + 4 with the X axis is
