Advertisements
Advertisements
प्रश्न
Solve the following simultaneous equations by the substitution method:
5x + 4y - 23 = 0
x + 9 = 6y
उत्तर
The given equations are
5x + 4y - 23 = 0 ....(i)
x + 9 = 6y ....(ii)
Now, consider equation
x + 9 = 6y
⇒ x = 6y - 9 ....(iii)
Substituting the value of x in eqn. (i), we get
5(6y - 9) + 4y - 23 = 0
⇒ 30y - 45 + 4y - 23 = 0
⇒ 34y - 68 = 0
⇒ 34y = 68
⇒ y = `(68)/(34)` = 2
Putting the value of y in eqn. (iii), we get
x = 6(2) - 9
= 12 - 9
= 3
Thus, the solution set is (3, 2).
APPEARS IN
संबंधित प्रश्न
Solve the pair of linear (simultaneous) equation by the method of elimination by substitution :
8x + 5y = 9
3x + 2y = 4
Solve the pair of linear (simultaneous) equation by the method of elimination by substitution :
2x - 3y = 7
5x + y= 9
Solve the pair of linear (simultaneous) equation by the method of elimination by substitution:
2x + 3y = 8
2x = 2 + 3y
Solve the following pair of linear (simultaneous) equation by the method of elimination by substitution:
0.2x + 0.1y = 25
2(x - 2) - 1.6y = 116
Solve the pair of linear (simultaneous) equation by the method of elimination by substitution:
6x = 7y + 7
7y - x = 8
Solve the following pair of linear (simultaneous) equation using method of elimination by substitution :
2x - 3y + 6 = 0
2x + 3y - 18 = 0
Solve the following simultaneous equations by the substitution method:
x + 3y= 5
7x - 8y = 6
Solve the following simultaneous equations by the substitution method:
2x + 3y = 31
5x - 4 = 3y
Solve the following simultaneous equations by the substitution method:
0.4x + 0.3y = 1.7
0.7x - 0.2y = 0.8
Solve the following simultaneous equations by the substitution method:
3 - (x + 5) = y + 2
2(x + y) = 10 + 2y
Solve the following pairs of equations:
`(6)/(x + y) = (7)/(x - y) + 3`
`(1)/(2(x + y)) = (1)/(3( x - y)`
Where x + y ≠ 0 and x - y ≠ 0
If a number is thrice the other and their sum is 68, find the numbers.
The sum of four times the first number and three times the second number is 15. The difference of three times the first number and twice the second number is 7. Find the numbers.
Solve by the method of elimination
2x – y = 3, 3x + y = 7
Solve by the method of elimination
x – y = 5, 3x + 2y = 25
Solve by the method of elimination
`4/x + 5y` = 7, `3/x + 4y` = 5