Question

Solve the following system of linear equations algebraically:

2x + 5y = −4; 4x − 3y = 5

Answer 1

Let, 2x + 5y = −4       ...(i)

and 4x − 3y = 5   ...(ii)

from equation (i) × 2 − equation (ii), we get 

4x + 10y = −8

4x − 3y  = 5       ...{by method of elimination}

−   +     −         
      13y = − 8 − 5

y = `(-13)/13 = -1`

Putting the value of y = −1 in (i) we get

2x + 5 × (−1) = −4

⇒ 2x = + 5 − 4

`x = 1/2` So, `x = 1/2`

y = −1