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प्रश्न
Solve for x and y:
23x - 29y = 98, 29x - 23y = 110
उत्तर
The given equations are:
23x - 29y = 98 …..(i)
29x - 23y = 110 ……(ii)
Adding (i) and (ii), we get:
52x – 52y = 208
⇒x – y = 4 ……(iii)
Subtracting (i) from (ii), we get:
6x + 6y = 12
⇒x + y = 2 ……(iv)
Now, adding equation (iii) and (iv), we get:
2x = 6
⇒x = 3
On substituting x = 3 in (iv), we have:
3 + y = 2
⇒y = 2 – 3 = -1
Hence, x = 3 and y = -1.
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