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प्रश्न
Subtract:
3t4 – 4t3 + 2t2 – 6t + 6 from – 4t4 + 8t3 – 4t2 – 2t + 11
उत्तर
We have,
3t4 – 4t3 + 2t2 – 6t + 6 and – 4t4 + 8t3 – 4t2 – 2t + 11
The required difference is given by (– 4t4 + 8t3 – 4t2 – 2t + 11) – (3t4 – 4t3 + 2t2 – 6t + 6)
= – 4t4 + 8t3 – 4t2 – 2t + 11 – 3t4 + 4t3 – 2t2 + 6t – 6
= (– 4t4 – 3t4) + (8t3 + 4t3) + (– 4t2 – 2t2) + (–2t + 6t) + (11 – 6) ...[Grouping like terms]
= –7t4 + 12t3 – 6t2 + 4t + 5
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