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प्रश्न
Subtract:
6x2 – 4xy + 5y2 from 8y2 + 6xy – 3x2
उत्तर
We have,
6x2 – 4xy + 5y2 and 8y2 + 6xy – 3x2
The required difference is given by (8y2 + 6xy – 3x2) – (6x2 – 4xy + 5y2)
= 8y2 + 6xy – 3x2 – 6x2 + 4xy – 5y2
= (8y2 – 5y2) + (6xy + 4xy) – (3x2 + 6x2)
= 3y2 + 10xy – 9x2
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संबंधित प्रश्न
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