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Subtract: 6x2 – 4xy + 5y2 from 8y2 + 6xy – 3x2 - Mathematics

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Question

Subtract:

6x2 – 4xy + 5y2 from 8y2 + 6xy – 3x2 

Sum

Solution

We have,

6x2 – 4xy + 5y2 and 8y2 + 6xy – 3x2 

The required difference is given by (8y2 + 6xy – 3x2) – (6x2 – 4xy + 5y2)

= 8y2 + 6xy – 3x2 – 6x2 + 4xy – 5y2

= (8y2 – 5y2) + (6xy + 4xy) – (3x2 + 6x2)

= 3y2 + 10xy – 9x2

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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 230]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 7 Algebraic Expression, Identities and Factorisation
Exercise | Q 82. (ii) | Page 230
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