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Question
Subtract:
2ab2c2 + 4a2b2c – 5a2bc2 from –10a2b2c + 4ab2c2 + 2a2bc2
Solution
We have,
2ab2c2 + 4a2b2c – 5a2bc2 and –10a2b2c + 4ab2c2 + 2a2bc2
The required difference is given by (–10a2b2c + 4ab2c2 + 2a2bc2) – (2ab2c2 + 4a2b2c – 5a2bc2)
= –10a2b2c + 4ab2c2 + 2a2bc2 – 2ab2c2 – 4a2b2c + 5a2bc2
= (–10a2b2c – 4a2b2c) + (4ab2c2 – 2ab2c2) + (2a2bc2 + 5a2bc2) ...[Grouping like terms]
= –14a2b2c + 2ab2c2 + 7a2bc2
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