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प्रश्न
Suggest the route for the preparation of the following from benzene.
m - dinitro benzene
उत्तर
Benzene undergo twice the time nitration to give m-dinitrobenzene.
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{............................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH_3}\phantom{.................................}
\end{array}\]
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