Advertisements
Advertisements
प्रश्न
Sum of the roots of a quadratic equation is double their product. Find k if equation x2 – 4kx + k + 3 = 0
उत्तर
Let the root be α and β
According to the given condition
α + β = 2 α.β
α + β = `(-b)/a` αβ = `c/a`
`(-b)/a` = 2 `c/a`
- b = 2c ...(i)
Compare with ax2 + bx + c = 0
x2 - 4kx + k + 3 = 0
a = 1, b = -4k, c = k + 3
Substituting the values in equation (i)
-b = 2c
-(-4k) = 2 (k + 3)
∴ 4k = 2k + 6
∴ 4k - 2k = 6
∴ 2k = 6
∴ k = `6/2`
∴ k = 3
APPEARS IN
संबंधित प्रश्न
Find the roots of the quadratic equation 4x2 + 4√3x + 3 = 0
Find the roots of the quadratic equation 2x2 + x + 4 = 0
The difference of squares of two numbers is 180. The square of the smaller number is 8 times the larger number. Find the two numbers
Sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, find the sides of the two squares.
Two taps running together can fill a tank in `3 1/13` hours. If one tap takes 3 hours more than the other to fill the tank, then how much time will each tap take to fill the tank?
Find the roots of the following quadratic equations (if they exist) by the method of completing the square.
3x2 + 11x + 10 = 0
Find the roots of the following quadratic equations (if they exist) by the method of completing the square.
`sqrt2x^2-3x-2sqrt2=0`
`sqrt2x^3-3x-2sqrt2=0`
A farmer prepares rectangular vegetable garden of area 180 sq meters. With 39 meters of barbed wire, he can fence the three sides of the garden, leaving one of the longer sides unfenced. Find the dimensions of the garden.
The ratio of the sum and product of the roots of the equation `7x^2-12x+18=0` is
(a) 7:12 (b)7:18 (c)3:2 (d)2:3
Fill in the gaps and complete.
If α, β are roots of quadratic equation,
Find the value of discriminant.
x2 + 7x – 1 = 0
Form the quadratic equation from the roots given below.
0 and 4
The difference of two natural numbers is 3 and the difference of their reciprocals is \[\frac{3}{28}\].Find the numbers.
The sum of the squares of two consecutive multiples of 7 is 637. Find the multiples.
The value of \[\sqrt{6 + \sqrt{6 + \sqrt{6 +}}} . . . .\] is
Complete the following activity to solve the given word problem. The Sum of squares of two consecutive even natural numbers is 244, then find those numbers.
Activity: Let the first even natural number be x
Therefore its consecutive even natural number will be = (______)
By the given condition,
x2 + (x + 2)2 = 244
x2 + x2 + 4x + 4 – (______) = 0
2x2 + 4x – 240 = 0
x2 + 2x – 120 = 0
x2 + (______) – (______) – 120 = 0
x(x + 12) – (______) (x + 12) = 0
(x + 12)(x – 10) = 0
x = (______)/x = 10
But natural number cannot be negative, x = – 12 is not possible.
Therefore first even natural number is x = 10.
Second even consecutive natural number = x + 2 = 10 + 2 = 12.
Find the value of x, if `(4/7)^x (7/4)^(2x) = 343/64`.