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प्रश्न
The value of \[\sqrt{6 + \sqrt{6 + \sqrt{6 +}}} . . . .\] is
पर्याय
4
3
-2
3.5
उत्तर
Let `x = sqrt(6 +sqrt(6+sqrt(6+sqrt(6+).....`
Squaring both sides we get
`x = sqrt(6 +sqrt(6+sqrt(6+sqrt(6+).....`
`x^2 = 6 + x`
`x^2 - x - 6 = 0`
`x^2 = 3x + 2x - 6 = 0`
`x (x - 3) + 2(x - 3) = 0`
`(x - 3)(x + 2) = 0`
(x - 3) = 0
x = 3
or
(x +2) = 0
x = -2
The value of x cannot be negative.
Thus, the value of x = 3
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