Advertisements
Advertisements
प्रश्न
The 1st, 3rd, and 4th terms of a proportion are 12, 8, and 14 respectively. Find the 2nd term.
उत्तर
Let the second term be x.
Then. 12 : x :: 8 : 14
We know:
Product of extremes = Product of means
12 × 14 = 8x
⇒ 168 = 8x
⇒ x = `168/8` = 21
Hence, the second term is 21.
APPEARS IN
संबंधित प्रश्न
Given four quantities a, b, c and d are in proportion. Show that: (a – c)b2 : (b – d)cd = (a2 – b2 – ab) : (c2 – d2 – cd)
Check whether the following numbers are in continued proportion.
2, 4, 8
If Rs 760 is divided between A and B in the ratio 8 : 11, then B's share is
If y is mean proportional between x and z, prove that xyz (x + y + z)³ = (xy + yz + zx)³.
If a, b, c are in continued proportion, prove that: a2 b2 c2 (a-4 + b-4 + c-4) = b-2(a4 + b4 + c4)
Find the missing number in the box in the proportions:
`16/36 = square/63 = 36/square = square/117`
Determine if the following are in proportion.
4, 6, 8, 12
Write True (T) or False (F) against the following statement:
0.9 : 0.36 : : 10 : 4
Unequal masses will not balance on a fulcrum if they are at equal distance from it; one side will go up and the other side will go down.
Unequal masses will balance when the following proportion is true:
`("mass"1)/("length"2) = ("mass"2)/("length"1)`
Two children can be balanced on a seesaw when
`("mass"1)/("length"2) = ("mass"2)/("length"1)`. The child on the left and child on the right are balanced. What is the mass of the child on the right?
A student said that the ratios `3/4` and `9/16` were proportional. What error did the student make?