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प्रश्न
The 9th term of an A.P. is 449 and 449th term is 9. The term which is equal to zero is
पर्याय
501th
502th
508th
none of these
उत्तर
In the given problem, let us take the first term as a and the common difference as d.
Here, we are given that,
`a_9 = 449` ...............(1)
`a_449 = 9 ` .................(2)
We need to find n
Also, we know,
`a_n = a + ( n- 1) d`
For the 9th term (n = 9),
`a_9 = a + ( 9 -1) d`
449 = a + 8d (Using 1 )
a = 449 - 8 d .................(3)
Similarly, for the 449th term (n = 449),
`a_449 = a + ( 449 - 1 )d`
9 = a + 448d (Using 2 )
a = 9 - 448 d .............(4)
Subtracting (3) from (4), we get,
a -a = ( 9 - 448d) - ( 449 - 8d)
0 = 9 - 448d - 449 + 8d
0 = -440 - 440d
440d = - 440
d = - 1
Now, to find a, we substitute the value of d in (3),
a = 449 - 8 (-1)
a = 449 + 8
a = 457
So, for the given A.P d = - 1 and a = 457
So, let us take the term equal to zero as the nth term. So,
`a_n = 457 + ( n- 1) ( -1 ) `
0 = 457 - n + 1
n = 458
So, n = 458
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