Advertisements
Advertisements
प्रश्न
The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3 : 2. Find their present ages.
उत्तर
Let the present age of B be x years.
Then, the present age of A = (x + 5) years
Five years ago, age of A = x + 5 – 5 = x years
And age of B = (x – 5) years
According to the question,
`x/(x - 5) = 3/2`
⇒ 2x = 3(x – 5)
⇒ 2x = 3x – 15
⇒ 3x – 2x = 15
∴ x = 15
Hence, the present age of B is 15 years and the present age of A is (15 + 5), i.e. 20 years.
APPEARS IN
संबंधित प्रश्न
Solve: `z/(z + 15) = 4/9`
Solve: `(3y + 4)/(2 - 6y) = (-2)/5`
The ages of Hari and Harry are in the ratio 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages.
The difference between the squares of two consecutive numbers is 31. Find the numbers.
Find a number such that when 5 is subtracted from 5 times the number, the result is 4 more than twice the number.
Divide 184 into two parts such that one-third of one part may exceed one-seventh of another part by 8.
The ages of sonu and Monu are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.
At a party, colas, squash and fruit juice were offered to guests. A fourth of the guests drank colas, a third drank squash, two fifths drank fruit juice and just three did not drink any thing. How many guests were in all?
Bhagwanti inherited Rs 12000.00. She invested part of it as 10% and the rest at 12%. Her annual income from these investments is Rs 1280.00. How much did she invest at each rate?
Solve the following:
`(5x)/(2x - 1) = 2`
