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Question
The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3 : 2. Find their present ages.
Solution
Let the present age of B be x years.
Then, the present age of A = (x + 5) years
Five years ago, age of A = x + 5 – 5 = x years
And age of B = (x – 5) years
According to the question,
`x/(x - 5) = 3/2`
⇒ 2x = 3(x – 5)
⇒ 2x = 3x – 15
⇒ 3x – 2x = 15
∴ x = 15
Hence, the present age of B is 15 years and the present age of A is (15 + 5), i.e. 20 years.
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