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The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3 : 2. Find their present ages. - Mathematics

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Question

The age of A is five years more than that of B. 5 years ago, the ratio of their ages was 3 : 2. Find their present ages.

Sum

Solution

Let the present age of B be x years.

Then, the present age of A = (x + 5) years

Five years ago, age of A = x + 5 – 5 = x years

And age of B = (x – 5) years

According to the question,

`x/(x - 5) = 3/2`

⇒ 2x = 3(x – 5)

⇒ 2x = 3x – 15

⇒ 3x – 2x = 15

∴ x = 15

Hence, the present age of B is 15 years and the present age of A is (15 + 5), i.e. 20 years.

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Chapter 4: Linear Equation In One Variable - Exercise [Page 119]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 4 Linear Equation In One Variable
Exercise | Q 97. | Page 119

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