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प्रश्न
The amplitude of sound is doubled and the frequency is reduced to one fourth. The intensity of sound at the same point will be ____________.
पर्याय
increased to double
increased to four times
decreased to half
decreased to one fourth
MCQ
रिकाम्या जागा भरा
उत्तर
The amplitude of sound is doubled and the frequency is reduced to one fourth. The intensity of sound at the same point will be decreased to half.
Explanation:
`"I" prop "A"^2 "n"^2`
`therefore "I"_1/"I"_2 = ("A"_1/"A"_2)^2 ("n"_1/"n"_2)^2`
` = ("A"/(2"A"))^2 ((4"n")/"n")^2`
` = 16/4 = 4`
`therefore "I"_2 = "I"_1/4`
shaalaa.com
Amplitude (A), Period (T) and Frequency (N) of S.H.M.
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