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The amplitude of sound is doubled and the frequency is reduced to one fourth. The intensity of sound at the same point will be ____________. -

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Question

The amplitude of sound is doubled and the frequency is reduced to one fourth. The intensity of sound at the same point will be ____________.

Options

  • increased to double

  • increased to four times

  • decreased to half

  • decreased to one fourth

MCQ
Fill in the Blanks

Solution

The amplitude of sound is doubled and the frequency is reduced to one fourth. The intensity of sound at the same point will be decreased to half.

Explanation:

`"I" prop "A"^2 "n"^2`

`therefore "I"_1/"I"_2 = ("A"_1/"A"_2)^2 ("n"_1/"n"_2)^2`

` = ("A"/(2"A"))^2 ((4"n")/"n")^2`

` = 16/4 = 4`

`therefore "I"_2 = "I"_1/4`

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Amplitude (A), Period (T) and Frequency (N) of S.H.M.
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