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Question
The amplitude of sound is doubled and the frequency is reduced to one fourth. The intensity of sound at the same point will be ____________.
Options
increased to double
increased to four times
decreased to half
decreased to one fourth
MCQ
Fill in the Blanks
Solution
The amplitude of sound is doubled and the frequency is reduced to one fourth. The intensity of sound at the same point will be decreased to half.
Explanation:
`"I" prop "A"^2 "n"^2`
`therefore "I"_1/"I"_2 = ("A"_1/"A"_2)^2 ("n"_1/"n"_2)^2`
` = ("A"/(2"A"))^2 ((4"n")/"n")^2`
` = 16/4 = 4`
`therefore "I"_2 = "I"_1/4`
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Amplitude (A), Period (T) and Frequency (N) of S.H.M.
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