Advertisements
Advertisements
प्रश्न
The area of a trapezium is 475 cm2 and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.
उत्तर
Given: Area of a trapezium = 475 cm2 and Height = 19 cm.
According to the question, let one sides of trapezium is x. So, another side will be x + 4.
Now, Area of trapezium = `1/2` × (Sum of the parallel sides) × Height
`475 = 1/2 xx (x + x + 4) xx 19 cm`
`2x + 4 = 950/19 = 50`
2x = 50 – 4
2x = 46
x = 23
Therefore, the length of the parallel side of trapezium are x = 23 cm and x + 4 = 23 + 4 = 27 cm.
APPEARS IN
संबंधित प्रश्न
Find the area of the triangle ABC with A(1, −4) and mid-points of sides through A being (2, −1) and (0, −1).
Find the area of the triangle whose vertices are: (2, 3), (-1, 0), (2, -4)
Show that the points O(0,0), A`( 3,sqrt(3)) and B (3,-sqrt(3))` are the vertices of an equilateral triangle. Find the area of this triangle.
Find the area of the following triangle:
If the points (2, -3), (k, -1), and (0, 4) are collinear, then find the value of 4k.
The area of the triangle ABC with the vertices A(-5, 7), B(-4, -5) and C(4, 5) is ______.
The area of a triangle with base 4 cm and height 6 cm is 24 cm2.
The area of ∆ABC is 8 cm2 in which AB = AC = 4 cm and ∠A = 90º.
A rectangular plot is given for constructing a house, having a measurement of 40 m long and 15 m in the front. According to the laws, a minimum of 3 m, wide space should be left in the front and back each and 2 m wide space on each of other sides. Find the largest area where house can be constructed.
In the given figure, ratio of the area of triangle ABC to the area of triangle ACD is the same as the ratio of base BC of triangle ABC to the base CD of ΔACD.
