Question

The average energy for molecules in one degree of freedom is ______.

पर्याय

• `3/2kT`

• `(kT)/2`

• `3/4kT`

• kT

Answer 1

The average energy for molecules in one degree of freedom is `underlinebb((kT)/2).`

Explanation:

Degree of freedom (for 1 molecule)

(f) = 1,

Average energy (E) = `f/2  "NkT" = (kT)/2`