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प्रश्न
The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be ______.
पर्याय
18,000 cm–1
16,000 cm–1
8,000 cm–1
20,000 cm–1
उत्तर
The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be 8,000 cm–1.
Explanation:
CFSE for octahedral and tetrahedral complex is related as
`Δ^t = 4/9 Δ_o`
Where `Δ_o` = CFSE for octahedral complex
`Δ_o` = CFSE for tetrahedral complex
`Δ_o` = 18000 cm–1
`Δ_t = 4/9 xx 18000` = 8000 cm–1
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संबंधित प्रश्न
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(i) \[\ce{[MnCl6]^{3-}}\]
(ii) \[\ce{[FeF6]^{3-}}\]
(iii) \[\ce{[CoF6]^{3-}}\]
(iv) \[\ce{[Ni(NH3)6]^{2+}}\]
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| Column I (Complex ion) | Column II (Hybridisation, number of unpaired electrons) |
| A. \[\ce{[Cr(H2O)6]^{3+}}\] | 1. dsp2, 1 |
| B. \[\ce{[Co(CN)4]^{2-}}\] | 2. sp3d2, 5 |
| C. \[\ce{[Ni(NH3)6]^{2+}}\] | 3. d2sp3, 3 |
| D. \[\ce{[MnF6]^{4-}}\] | 4. sp3, 4 |
| 5. sp3d2, 2 |
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