मराठी

The city traffic police issued challans for not observing the traffic rules: Day of the Week Mon Tue Wed Thus Fri Sat No. of Challans 40 24 36 58 62 80 Find Q.D. - Mathematics and Statistics

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प्रश्न

The city traffic police issued challans for not observing the traffic rules:

Day of the Week Mon Tue Wed Thus Fri Sat
No. of Challans 40 24 36 58 62 80

Find Q.D.

बेरीज

उत्तर

The given data can be arranged in ascending order as follows:
24, 36, 40, 58, 62, 80
Here, n = 6

Q1 = value of `(("n" + 1)/4)^"th"` observation

= value of `((6 + 1)/4)^"th"` observation

= value of (1.75)th observation
= value of 1st observation + 0.75 (value of 2nd observation – value of 1st observation)
= 24 + 0.75(36 – 24)
= 24 + 0.75 (12)
= 24 + 9
∴ Q1 = 33

Q3 = value of `3(("n" + 1)/4)^"th"` observation

= value of `3((6 + 1)/4)^"th"` observation

= value of (3 × 1.75)th observation
= value of (5.25)th observation
= value of 5th observation + 0.25 (value of 6th observation – value of 5th observation)
= 62 + 0.25(80 –  62)
= 62 + 0.25(18)
= 62 + 4.5
= 66.5
∴ Q.D. = `("Q"_3 - "Q"_1)/2`

= `(66.5 - 33)/2`

= `(33.5)/2`

= 16.75

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Measures of Dispersion - Quartile Deviation (Semi - Inter Quartile Range)
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Measures of Dispersion - Miscellaneous Exercise 2 [पृष्ठ ३५]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
पाठ 2 Measures of Dispersion
Miscellaneous Exercise 2 | Q 4 | पृष्ठ ३५
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