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The city traffic police issued challans for not observing the traffic rules: Day of the Week Mon Tue Wed Thus Fri Sat No. of Challans 40 24 36 58 62 80 Find Q.D. - Mathematics and Statistics

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Question

The city traffic police issued challans for not observing the traffic rules:

Day of the Week Mon Tue Wed Thus Fri Sat
No. of Challans 40 24 36 58 62 80

Find Q.D.

Sum

Solution

The given data can be arranged in ascending order as follows:
24, 36, 40, 58, 62, 80
Here, n = 6

Q1 = value of `(("n" + 1)/4)^"th"` observation

= value of `((6 + 1)/4)^"th"` observation

= value of (1.75)th observation
= value of 1st observation + 0.75 (value of 2nd observation – value of 1st observation)
= 24 + 0.75(36 – 24)
= 24 + 0.75 (12)
= 24 + 9
∴ Q1 = 33

Q3 = value of `3(("n" + 1)/4)^"th"` observation

= value of `3((6 + 1)/4)^"th"` observation

= value of (3 × 1.75)th observation
= value of (5.25)th observation
= value of 5th observation + 0.25 (value of 6th observation – value of 5th observation)
= 62 + 0.25(80 –  62)
= 62 + 0.25(18)
= 62 + 4.5
= 66.5
∴ Q.D. = `("Q"_3 - "Q"_1)/2`

= `(66.5 - 33)/2`

= `(33.5)/2`

= 16.75

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Measures of Dispersion - Quartile Deviation (Semi - Inter Quartile Range)
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Chapter 2: Measures of Dispersion - Miscellaneous Exercise 2 [Page 35]

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Balbharati Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
Chapter 2 Measures of Dispersion
Miscellaneous Exercise 2 | Q 4 | Page 35
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