Advertisements
Advertisements
प्रश्न
The class marks of a frequency distribution are given as follows: 15, 20, 25, ... The class corresponding to the class mark 20 is ______.
पर्याय
12.5 – 17.5
17.5 – 22.5
18.5 – 21.5
19.5 – 20.5
उत्तर
The class marks of a frequency distribution are given as follows: 15, 20, 25, ... The class corresponding to the class mark 20 is 17.5 – 22.5.
Explanation:
Since, the difference between mid-value is 5.
So, the corresponding class to the class mark 20 must have difference 5.
Therefore, option (c) and (d) are wrong.
Since, the mid-value is 20 which can get only, if we take
`(17.5 + 22.5)/2 = 40/2` = 20
APPEARS IN
संबंधित प्रश्न
Find the mean of 994, 996, 998, 1002 and 1000.
If M is the mean of x1 , x2 , x3 , x4 , x5 and x6, prove that
(x1 − M) + (x2 − M) + (x3 − M) + (x4 − M) + (x5 — M) + (x6 − M) = 0.
Find the mean of the following data:
| x : | 19 | 21 | 23 | 25 | 27 | 29 | 31 |
| f : | 13 | 15 | 16 | 18 | 16 | 15 | 13 |
The mean of the following data is 20.6. Find the value of p.
| x : | 10 | 15 | p | 25 | 35 |
| f : | 3 | 10 | 25 | 7 | 5 |
Find the median of the following observations : 46, 64, 87, 41, 58, 77, 35, 90, 55, 92, 33. If 92 is replaced by 99 and 41 by 43 in the above data, find the new median?
Mode is
Let m be the mid-point and l be the upper-class limit of a class in a continuous frequency distribution. The lower class limit of the class is ______.
There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be –3.5. The mean of the given numbers is ______.
A class consists of 50 students out of which 30 are girls. The mean of marks scored by girls in a test is 73 (out of 100) and that of boys is 71. Determine the mean score of the whole class.
Mean of 50 observations was found to be 80.4. But later on, it was discovered that 96 was misread as 69 at one place. Find the correct mean.
