Advertisements
Advertisements
Question
The class marks of a frequency distribution are given as follows: 15, 20, 25, ... The class corresponding to the class mark 20 is ______.
Options
12.5 – 17.5
17.5 – 22.5
18.5 – 21.5
19.5 – 20.5
Solution
The class marks of a frequency distribution are given as follows: 15, 20, 25, ... The class corresponding to the class mark 20 is 17.5 – 22.5.
Explanation:
Since, the difference between mid-value is 5.
So, the corresponding class to the class mark 20 must have difference 5.
Therefore, option (c) and (d) are wrong.
Since, the mid-value is 20 which can get only, if we take
`(17.5 + 22.5)/2 = 40/2` = 20
APPEARS IN
RELATED QUESTIONS
The following number of goals were scored by a team in a series of 10 matches:-
2, 3, 4, 5, 0, 1, 3, 3, 4, 3
Find the mean, median and mode of these scores.
If the heights of 5 persons are 140 cm, 150 cm, 152 cm, 158 cm and 161 cm respectively,
find the mean height.
Find the mean of x, x + 2, x + 4, x +6, x + 8.
The numbers of children in 10 families of a locality are:
2, 4, 3, 4, 2, 0, 3, 5, 1, 1, 5. Find the mean number of children per family.
Explain, by taking a suitable example, how the arithmetic mean alters by
(i) adding a constant k to each term
(ii) subtracting a constant k from each them
(iii) multiplying each term by a constant k and
(iv) dividing each term by a non-zero constant k.
The mean of 5 numbers is 18. If one number is excluded, their mean is 16. Find the excluded number.
Find the median of the following data (1-8)
12, 17, 3, 14, 5, 8, 7, 15
If the ratio of mode and median of a certain data is 6 : 5, then find the ratio of its mean and median.
Mode is
A total of 25 patients admitted to a hospital are tested for levels of blood sugar, (mg/dl) and the results obtained were as follows:
| 87 | 71 | 83 | 67 | 85 |
| 77 | 69 | 76 | 65 | 85 |
| 85 | 54 | 70 | 68 | 80 |
| 73 | 78 | 68 | 85 | 73 |
| 81 | 78 | 81 | 77 | 75 |
Find mean, median and mode (mg/dl) of the above data.
