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Question
Let m be the mid-point and l be the upper-class limit of a class in a continuous frequency distribution. The lower class limit of the class is ______.
Options
2m + l
2m – l
m – l
m – 2l
Solution
Let m be the mid-point and l be the upper-class limit of a class in a continuous frequency distribution. The lower class limit of the class is 2m – l.
Explanation:
Given: Mid-point = m
Upper class limit = 1
As, we know that, mid-point = `("Upper class-limit" + "Lower class-limit")/2`
So, `m = (l + "Lower class-limit")/2`
l + Lower class-limit = 2m
Lower class-limit = 2m – l
Hence, the lower class limit of the class is 2m – l.
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