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Question
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is ______.
Options
15
25
35
40
Solution 1
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is 35.
Explanation:
Let x and y be the upper and lower class limit of frequency distribution.
Given, width of the class = 5
⇒ x – y = 5 ...(i)
Also, given lower class (y) = 10
On putting y = 10 in equation (i), we get
x – 10 = 5
⇒ x = 15
So, the upper-class limit of the lowest class is 15.
Hence, the upper-class limit of the highest class
= (Number of continuous classes × Class width + Lower class limit of the lowest class)
= 5 × 5 + 10
= 25 + 10
= 35
Hence, the upper-class limit of the highest class is 35.
Solution 2
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is 35.
Explanation:
After finding the upper-class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10 – 15, 15 – 20, 20 – 25, 25 – 30 and 30 – 35.
Thus, the highest class is 30 – 35,
Hence, the upper limit of this class is 35.
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