मराठी

The contents of 100 match boxes were checked to determine the number of matches they contained. No. of matches 35 36 37 38 39 40 41 No. of boxes 6 10 18 25 21 12 8 - Mathematics

Advertisements
Advertisements

प्रश्न

The contents of 100 match boxes were checked to determine the number of matches they contained.

No. of matches 35 36 37 38 39 40 41
 No. of boxes 6 10 18 25 21 12 8
  1. Calculate, correct to one decimal place, the mean number of matches per box. 
  2. Determine, how many extra matches would have to be added to the total contents of the 100 boxes to bring the mean up to exactly 39 matches.
बेरीज

उत्तर

No. of matches
(x)
No. of boxes
(f)
fx 
 35 6 210
36 10 360
37 18 666
38 25 950
39 21 819
40 12 480
41 8 328
Total  100 3813 

i. `barx = (sumfx)/(sumf)`

= `3813/100`

= 38.13 

ii. In the second case,

New mean = 39 matches 

Total contents = 39 × 100 = 3900

But total number of matches already given = 3813 

Number of new matches to be added = 3900 – 3813 = 87

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 24: Measure of Central Tendency(Mean, Median, Quartiles and Mode) - Exercise 24 (A) [पृष्ठ ३५६]

APPEARS IN

सेलिना Mathematics [English] Class 10 ICSE
पाठ 24 Measure of Central Tendency(Mean, Median, Quartiles and Mode)
Exercise 24 (A) | Q 11 | पृष्ठ ३५६
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×