Question

The cross-section of two pistons in a hydraulic lift are 100 cm² and 800 cm² respectively. What is the minimum force required to lift 5000 kg-wt on a large piston surface? (in kN)

पर्याय

• 392

• 400

• 412

• 500

Answer 1

392

Explanation:

As we know F₁A₁ = F₂A₂

F₁ = `"F"_2 xx "A"_2/"A"_1`

= `5000 xx 9.8 xx 800/100`

F₁ = 5000 × 9.8 × 8

F₁ = 392000 N