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Question
The cross-section of two pistons in a hydraulic lift are 100 cm2 and 800 cm2 respectively. What is the minimum force required to lift 5000 kg-wt on a large piston surface? (in kN)
Options
392
400
412
500
MCQ
Solution
392
Explanation:
As we know F1A1 = F2A2
F1 = `"F"_2 xx "A"_2/"A"_1`
= `5000 xx 9.8 xx 800/100`
F1 = 5000 × 9.8 × 8
F1 = 392000 N
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Application of Pascal’s Law
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