Question

The equation of line passing through the midpoint of the line joining the points (-1, 3, -2) and (-5, 3, -6) and equally inclined to the axes is ______.

पर्याय

• x - 3 = y + 3 = z - 4

• x + 3 = y - 3 = z + 4

• x + 1 = y - 3 = z + 2

• x + 5 = y + 3 = z + 6

Answer 1

The equation of line passing through the midpoint of the line joining the points (-1, 3, -2) and (-5, 3, -6) and equally inclined to the axes is x + 3 = y - 3 = z + 4.

Explanation:

Let A= (-1, 3, -2) and B = (-5, 3, -6)

Midpoint of AB = (-3, 3,-4)

Since the line is equally inclined to the axis

∴ d.r.s are 1, 1, 1.

∴ equation of the line is `(x+3)/1=(y-3)/1=(z+4)/1`

⇒ x + 3 = y - 3 = z + 4