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प्रश्न
The equation λ = `1.227/"x"` nm can be used to find the de Brogli wavelength of an electron. In this equation x stands for:
Where,
m = mass of electron
P = momentum of electron
K = Kinetic energy of electron
V = Accelerating potential in volts for electron
पर्याय
`sqrt"mK"`
`sqrt"P"`
`sqrt"K"`
`sqrt"V"`
MCQ
उत्तर
`bb(sqrt"V")`
Explanation:
Wavelength, λ = `"h"/"p"="h"/"mv"`
⇒ λ = `"h"/(sqrt(2"m"("K"."E")))`
∴ `"h"/(sqrt("2mqV"))`
When m and q values are combined and solved, we get
λ = `1.22/sqrt"V"`nm
So x stands for `sqrt"V"`.
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