Question

The equation λ = `1.227/"x"` nm can be used to find the de Brogli wavelength of an electron. In this equation x stands for:

Where,

m = mass of electron

P = momentum of electron

K = Kinetic energy of electron

V = Accelerating potential in volts for electron

Options

• `sqrt"mK"`

• `sqrt"P"`

• `sqrt"K"`

• `sqrt"V"`

Answer 1

`bb(sqrt"V")`

Explanation:

Wavelength, λ = `"h"/"p"="h"/"mv"`

⇒ λ = `"h"/(sqrt(2"m"("K"."E")))`    

∴ `"h"/(sqrt("2mqV"))`

When m and q values are combined and solved, we get

λ = `1.22/sqrt"V"`nm

So x stands for `sqrt"V"`.