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प्रश्न
The general solution of the differential equation of all circles having centre at A(- 1, 2) is ______.
पर्याय
x2 + y2 + x - 2y + c = 0
x2 + y2 - 2x + 4y + c = 0
x2 + y2 - x + 2y + c = 0
x2 + y2 + 2x - 4y + c = 0
MCQ
रिकाम्या जागा भरा
उत्तर
The general solution of the differential equation of all circles having centre at A(- 1, 2) is x2 + y2 + 2x - 4y + c = 0.
Explanation:
General equation of a circle with centre (- g, - f) is
x2 + y2 + 2gx + 2fy + c = 0
If (- g, - f) = A (- 1, 2)
Then equation of circle,
x2 + y2 + 2x - 4y + c = 0
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Formation of Differential Equations
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