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The general solution of the differential equation of all circles having centre at A(- 1, 2) is ______. -

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Question

The general solution of the differential equation of all circles having centre at A(- 1, 2) is ______.

Options

  • x2 + y2 + x - 2y + c = 0

  • x2 + y2 - 2x + 4y + c = 0

  • x2 + y2 - x + 2y + c = 0

  • x2 + y2 + 2x - 4y + c = 0

MCQ
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Solution

The general solution of the differential equation of all circles having centre at A(- 1, 2) is x2 + y2 + 2x - 4y + c = 0.

Explanation:

General equation of a circle with centre (- g, - f) is

x2 + y2 + 2gx + 2fy + c = 0

If (- g, - f) = A (- 1, 2)

Then equation of circle,

x2 + y2 + 2x - 4y + c = 0

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Formation of Differential Equations
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