Question

The ground state energy of a hydrogen atom is - 13.6 eV When its electron is in the first excited state, its excitation energy is

पर्याय

• 3.4eV

• 10.2eV

• 6.8eV

• 13.6eV

Answer 1

3.4eV

Explanation:

The first enthusiastic state signifies n = 2

Energy E = `13.6/("n"^2)`

= `13.6/((2)^2)`

= 3.4 eV