Advertisements
Advertisements
Question
The ground state energy of a hydrogen atom is - 13.6 eV When its electron is in the first excited state, its excitation energy is
Options
3.4eV
10.2eV
6.8eV
13.6eV
MCQ
Solution
3.4eV
Explanation:
The first enthusiastic state signifies n = 2
Energy E = `13.6/("n"^2)`
= `13.6/((2)^2)`
= 3.4 eV
shaalaa.com
Is there an error in this question or solution?