Advertisements
Advertisements
प्रश्न
The largest oxidation number exhibited by an element depends on its outer electronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number?
पर्याय
3d14s2
3d34s2
3d54s1
3d54s2
उत्तर
3d54s2
Explanation:
Highest O.N. of any transition element = (n – 1)d electrons +ns electrons. Therefore, larger the number of electrons in the 3d orbitals, higher is the maximum O.N.
(i) 3d14s2 = 3
(ii) 3d24s2 = 3 + 2 = 5
(iii) 3d54s1 = 5 + 1 = 6
(iv) 3d54s2 = 5 + 2 = 7
APPEARS IN
संबंधित प्रश्न
Assign oxidation numbers to the underlined element in the following species:
NaHSO4
Assign oxidation numbers to the underlined elements in the following species:
CaO2
What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?
H2S4O6
Consider the elements : Cs, Ne, I and F
Identify the element which exhibits neither the negative nor does the positive oxidation state.
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
In which of the following compounds, an element exhibits two different oxidation states.
\[\ce{PbO}\] and \[\ce{PbO2}\] react with \[\ce{HCl}] according to following chemical equations:
\[\ce{2PbO + 4HCl -> 2PbCl2 + 2H2O}\]
\[\ce{PbO2 + 4HCl -> PbCl2 + Cl2 + 2H2O}\]
Why do these compounds differ in their reactivity?
Match Column I with Column II for the oxidation states of the central atoms.
| Column I | Column II |
| (i) \[\ce{Cr2O^{2-}7}\] | (a) + 3 |
| (ii) \[\ce{MnO^{-}4}\] | (b) + 4 |
| (iii) \[\ce{VO^{-}3}\] | (c) + 5 |
| (iv) \[\ce{FeF^{3-}6}\] | (d) + 6 |
| (e) + 7 |
The oxidation number of P in Mg2P207 is ____________.
In which of the following species oxidation number of the element(s) is equal to + 4?
