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Question
The largest oxidation number exhibited by an element depends on its outer electronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number?
Options
3d14s2
3d34s2
3d54s1
3d54s2
Solution
3d54s2
Explanation:
Highest O.N. of any transition element = (n – 1)d electrons +ns electrons. Therefore, larger the number of electrons in the 3d orbitals, higher is the maximum O.N.
(i) 3d14s2 = 3
(ii) 3d24s2 = 3 + 2 = 5
(iii) 3d54s1 = 5 + 1 = 6
(iv) 3d54s2 = 5 + 2 = 7
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