Question

The least count of the main scale of a screw gauge is 1 mm. The minimun number of divisions on its circular scale required to measure 5 µm diameter of a wire is ______.

पर्याय

• 50

• 200

• 100

• 500

Answer 1

The least count of the main scale of a screw gauge is 1 mm. The minimun number of divisions on its circular scale required to measure 5 µm diameter of a wire is 200.

Explanation:

Least count of main scale of M.S.D. is equal to pitch.

So pitch = 1 mm

Now, least count of screw gauge (L.C)

= `"Pitch"/"Number of division on circular scale"`

⇒ no. of div (n) = `"Pitch"/"L.C"`

⇒ n = `(1  "mm")/(5mu"m")`

⇒ n = 200