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Question
The least count of the main scale of a screw gauge is 1 mm. The minimun number of divisions on its circular scale required to measure 5 µm diameter of a wire is ______.
Options
50
200
100
500
MCQ
Fill in the Blanks
Solution
The least count of the main scale of a screw gauge is 1 mm. The minimun number of divisions on its circular scale required to measure 5 µm diameter of a wire is 200.
Explanation:
Least count of main scale of M.S.D. is equal to pitch.
So pitch = 1 mm
Now, least count of screw gauge (L.C)
= `"Pitch"/"Number of division on circular scale"`
⇒ no. of div (n) = `"Pitch"/"L.C"`
⇒ n = `(1 "mm")/(5mu"m")`
⇒ n = 200
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