मराठी
सी.आई.एस.सी.ई.आयसीएसई ICSE Class 8

The Length of a Hall is 18 M and Its Width is 13.5 M. Find the Least Number of Square Tiles, Each of Side 25 Cm, Required to Cover the Floor of the Hall, (I) Without Leaving Any Margin. - Mathematics

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प्रश्न

The length of a hall is 18 m and its width is 13.5 m. Find the least number of square tiles, each of side 25 cm, required to cover the floor of the hall,

(i) without leaving any margin.
(ii) leaving a margin of width 1.5 m all around. In each case, find the cost of the tiles required at the rate of Rs. 6 per tile

बेरीज

उत्तर

(i)

Length of hall (l) = 18 m and breadth (b) = 13.5 m

∴ Area of the floor = l × b

=`18 xx 13.5  "m"^2 = 243.0  "m"^2`

Side of each square tiles (a) = 25 cm

= `25/100 = 1/4`m

∴ Area of one tile = a2 = `1/4 xx 1/4`

= `1/16  "m"^2`

No. of tiles required = `243 + 1/16`

= `(243 xx 16)/1 = 3888`

Rate of tiles = Rs. 6 per tile

∴ Total cost = Rs. 3888 × 6

= Rs. 23328

(ii)

Width of margin left in side = 1.5 m

∴ Inner length = `18 - 2 xx 1.5 = 18 - 3 = 15` m

and breath = `13.5 - 2 xx 1.5 = 13.5 - 3`

= 10.5 m

∴ Inner area = `15 xx 10.5  "m"^2`

= 157.5 m2

∴ No. of tiles = 157.5 + `1/16`

= `157.5 xx 16 = 2520`

∴ Cost of tiles = 2520 × 6 = Rs. 15120

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पाठ 20: Area of a Trapezium and a Polygon - Exercise 20 (B) [पृष्ठ २२७]

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सेलिना Concise Mathematics [English] Class 8 ICSE
पाठ 20 Area of a Trapezium and a Polygon
Exercise 20 (B) | Q 16 | पृष्ठ २२७
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