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प्रश्न
The magnetic field lines in the middle of the current-carrying solenoid are?
(a) circles
(b) spirals
(c) parallel to the axis of the tube
(d) perpendicular to the axis of the tube
उत्तर
parallel to the axis of the tube
The magnetic field lines in the middle of a current-carrying solenoid are parallel to the axis of the tube because magnetic field is uniform inside a solenoid.
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संबंधित प्रश्न
Observe the following figure:
If the current in the coil A is changed, will some current be induced in the coil B? Explain.
What is the shape of field lines inside a current-carrying solenoid? What does the pattern of field lines inside a current-carrying solenoid indicate?
List three ways in which the magnetic field strength of a current-carrying solenoid can be increased?
A soft iron bar is inserted inside a current-carrying solenoid. The magnetic field inside the solenoid:
(a) will decrease
(b) will increase
(c) will become zero
(d) will remain the same
The magnetic field associated with a current-carrying straight conductor is in anticlockwise direction. If the conductor was held along the east-west direction, what will be the direction of current through it? Name and state the rule applied to determine the direction of current?
i) Which principle is explained in this figure?
ii) Which rule is used to find out the direction of a force in this principle?
iii) In which machine this principle is used? Draw a diagram showing working of that machine
Differentiate between Conductors and insulators.
A magnetic field directed in north direction acts on an electron moving in east direction. The magnetic force on the electron will act ____________.
The diagram below shows a free conductor AB is kept in a magnetic field and is carrying current from A to B. (To avoid confusion complete path of the circuit is not shown) The direction of the force experienced by the conductor will be:
Describe the activity that shows that a current-carrying conductor experiences a force perpendicular to its length and the external magnetic field. How does Fleming’s left-hand rule help us to find the direction of the force acting on the current carrying conductor?
