मराठी

The Mean of N Observation is ¯¯¯ X . If the First Observation is Increased by 1, the Second by 2, the Third by 3, and So On, Then the New Mean is - Mathematics

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प्रश्न

The mean of n observation is `overlineX`.  If the first observation is increased by 1, the second by 2, the third by 3, and so on, then the new mean is

पर्याय

  • `overlineX`\[ + \left( 2n + 1 \right)\]
  • `overlineX`\[+ \frac{n + 1}{2}\]
  • `overlineX`\[ + \left( n + 1 \right)\]
  • `overlineX`\[ - \frac{n + 1}{2}\]

MCQ

उत्तर

Let \[x_1 , x_2 , x_3 , . . . , x_n\] be the n observations.

Mean = `overlineX`\[= \frac{x_1 + x_2 + . . . + x_n}{n}\]

\[\Rightarrow x_1 + x_2 + x_3 + . . . + x_n = n\]`overlineX`

If the first item is increased by 1, the second by 2, the third by 3 and so on.

Then, the new observations are

\[x_1 + 1, x_2 + 2, x_3 + 3, . . . , x_n + n\].

New mean = \[\frac{\left( x_1 + 1 \right) + \left( x_2 + 2 \right) + \left( x_3 + 3 \right) + . . . + \left( x_n + n \right)}{n}\]

\[= \frac{x_1 + x_2 + x_3 + . . . + x_n + \left( 1 + 2 + 3 + . . . + n \right)}{n}\]

`= (nx +(n(n+1))/2)/n`

`=overlineX`\[ + \frac{n + 1}{2}\]

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पाठ 15: Statistics - Exercise 15.8 [पृष्ठ ६७]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 15 Statistics
Exercise 15.8 | Q 23 | पृष्ठ ६७
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