Advertisements
Advertisements
प्रश्न
The molecular formulae of some organic compounds are given below. Which of these compounds contains an aldehyde group?
(a) C3H8O
(b) C3H6O2
(c) C3H6O
(d) C3H7Cl
उत्तर
C3H6O contains an aldehyde group, as the compound satisfies the general formula of the aldehydes CnH2nO.
APPEARS IN
संबंधित प्रश्न
Write the number of covalent bonds in the molecule of propane, C3H8.
Write the names and structural formulae of all the possible isomers of hexane.
Give the name and structural formula of one member each of the following:
alkyne
Explain the meaning of saturated and unsaturated hydrocarbons with two examples each.
How many isomers of the following hydrocharbons are possible?
C5H12
Two organic compounds A and B have the same molecular formula C6H12. Write the names and structural formulae:
Which compound contains single bonds as well as a double bond?
Name the functional group which always occurs in the middle of a carbon chain.
Three organic compounds A, B and C have the following molecular formulae: C4H8O
Which molecular formula can represent an aldehyde as well as a ketone? Write the names and structural formulae of the aldehyde and ketone represented by this molecular formula.
Match the reactions given in Column (A) with the names given in column (B).
| Column (A) | Column (B) | ||
(a) |
`"CH"_3"OH" + "CH"_3"COOH"overset("H"^+)(->) "CH"_3"COOCH"_3 + "H"_2"O"` | (i) | Addition reaction |
| (b) | `"CH"_3 = "CH"_2 + "H"_2 overset("Ni")(->)"CH"_3 - "CH"_3` | (ii) | Substitution reaction |
| (c) | `"CH"_4 + "Cl"_2overset("Sunlight")(->)"CH"_3"Cl" + "HCl"` | (iii) | Neutralisation reaction |
| (d) | `"CH"_3"COOH" + "NaOH" -> "CH"_3"COONa" + "H"_2"O"` | (iv) | Esterification reaction |
Recognise the carbon chain type of the following:
\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\\ce{H - C - C - C - C - H}\\|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]
