Advertisements
Advertisements
प्रश्न
The most commonly used reducing agent is ______.
पर्याय
AlCl3
PbCl2
SnCl4
SnCl2
उत्तर
The most commonly used reducing agent is SnCl2.
Explanation:
+4 oxidation state of Sn is more stable than +2 oxidation state. Therefore, Sn2+ can be easily oxidised to Sn4+ and hence SnCl2 acts a reducing agent.
\[\ce{SnCl2 + 2Cl -> SnCl4 + 2e–}\]
APPEARS IN
संबंधित प्रश्न
How can you explain higher stability of BCl3 as compared to TlCl3?
What happens when BF3 is reacted with ammonia?
Which of the following oxides is acidic in nature?
Explain why the following compounds behave as Lewis acids?
BCl3
Describe the general trends in the following properties of the elements in Groups 13 and 14.
Oxidation states
Account for the following observations:
The +1 oxidation state of thallium is more stable than its +3 state.
Three pairs of compounds are given below. Identify that compound in each of the pairs which has group 13 element in more stable oxidation state. Give reason for your choice. State the nature of bonding also.
AlCl3 , AlCl
Three pairs of compounds are given below. Identify that compound in each of the pairs which has group 13 element in more stable oxidation state. Give reason for your choice. State the nature of bonding also.
InCl3, InCl
Boron fluoride exists as BF3 but boron hydride doesn’t exist as BH3. Give reason. In which form does it exist? Explain its structure.
Boron compounds behave as Lewis acids because of their ______.