Question

The oxidation number of phosphorous in Ba(H₂PO₂)₂ is ______.

पर्याय

• - 3

• + 3

• + 5

• + 1

Answer 1

The oxidation number of phosphorous in Ba(H₂PO₂)₂ is + 1.

Explanation:

Ba(H₂PO₂)₂ 

O.S. (Ba) + O.S. (4H) + O.S. (2P) + O.S. (4O) = 0

2 + 4 + 2P + (- 8) = 0

2P - 2 = 0

2P = + 2     ∴ P = + 1

Oxidation State of P = + 1